KSEEB Solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1

In this chapter, we provide KSEEB Solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB Solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1 pdf, free KSEEB solutions for Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1 book pdf download. Now you will get step by step solution to each question.

Karnataka Board Class 9 Maths Chapter 10 Linear Equations in Two Variables Ex 10.1

Question 1.
The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement. (Take the cost of a notebook to be Rs. x and that of a pen to be Rs. y).
Solution:
Let the cost of pen b Rs. x
If the cost of the Notebook is Rs. y.
Cost of 1 notebook is twice the cost of a pen.
∴ y = 2x
-2x + y = 0
If this is written in the form of
ax + by + c = 0 it is
-2x + y + 0 = 0
Here, a = -2, b = 1, c = 0.

Question 2.
Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:
i) 2x + 3y = (9 . overline{35})
ii) x – (frac{y}{5}) – 10 = 0
iii) -2x + 3y = 6
iv) x = 3y
v) 2x = -5y
vi) 3x + 2 = 0
vii) y – 2 = 0
viii) 5 = 2x
Solution:
i) 2x + 3y = (9 . overline{35})
OR 2x + 3y – (9 . overline{35}) = 0
If we compare this to ax + by + c = 0,
Here, a = 2, b = 3, c = (9 . overline{35}).

ii) x – (frac{y}{5}) – 10 = 0
If we compare this to ax + by + c = 0,
Here, a = 1, b = (frac{-1}{5}) , c=10.

iii) -2x + 3y = 6
OR -2x + 3y – 6 = 0
If we compare this to ax + by + c = 0,
Here, a = -2, b = 3, c = -6.

iv) x = 3y
x – 3y = 0
x – 3y + 0 = 0
If we compare this to ax + by + c = 0,
Here, a = 1, b = -3, c = 0.

v) 2x = -5y
2x + 5y = 0
2x + 5y + 0 = 0
If we compare this to ax + by + c = 0,
Here, a = 2, b = 5, c = 0.

vi) 3x + 2 = 0
3x + 0y + 2 = 0
If we compare this to ax + by + c = 0,
Here, a = 3, b = 0, c = 2.

vii) y – 2 = 0
0x + 1y – 2 = 0
If we compare this to ax + by + c = 0,
Here, a = 0, b = 1, c = -2.

viii) 5 = 2x
-2x + 5 = 0
-2x + 0y + 5 = 0
If we compare this to ax + by + c = 0,
Here, a = -2, b = 0, c = 5.

All Chapter KSEEB Solutions For Class 9 Maths

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All Subject KSEEB Solutions For Class 9

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