KSEEB Solutions for Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2

In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2 pdf, free KSEEB SSLC Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2 pdf download. Now you will get step by step solution to each question.

Karnataka State Syllabus Class 8 Maths Chapter 9 Commercial Arithmetic Ex 9.2

Question 1.
Sonu bought a bicycle for Rs. 3750 and spent Rs. 250 on its repairs. He sold it for Rs. 4400. Find his loss or profit percentage.
Answer:
C.P = 3750 + 250 = Rs. 4000 S P = Rs. 4400
S.P > C.P
∴ S.P – C.P = 4400 – 4000 = Rs. 400
Protit percent = \frac { profit }{ C.P } × 100
\frac { 400}{ 4000 } × 100 = 10
Profit percent = 10%

Question 2.
A shop keeper purchases an article for Rs. 3500 and pays the transport charge of Rs. 100. He incurred a loss of 12% in selling this. Find selling price of the article.
Answer:
C.P = 3500 + 100 = Rs. 3600
Loss percent = 12%
KSEEB Solutions for Class 8 Maths Chapter 9 Commercial Arithmetic Ex. 9.2 1
S.P = Rs.3168.

Question 3.
By selling a watch for Rs. 720, Ravi loses 10%. At what price should he sell it, in order to gain 15% .
Answer:
S.P = Rs. 720,
loss percent = 10% C.P = ?
CP=100(100− Loss percent )×SP=100(100−10)×720=10090×720
C.P = RS. 800
gain percent = 15 %
S.P = ?
S.P=(100+gain%)100×C.P=100+15100×800=115100×800
S.P = Rs. 920
He should sell it for Rs. 920 to gain a 15% profit.

Question 4.
Hari bought two fans for Rs. 2400 each. He sold one at a loss of 10% and the other at a profit of 15%. Find the selling price of each fan and also the total profit or loss.
Answer:
C.P = Rs. 2400, Loss% = 10%
S.P = ?
KSEEB Solutions for Class 8 Maths Chapter 9 Commercial Arithmetic Ex. 9.2 2
S.P = Rs. 2160
∴ When the loss percent is 10% S.P. is Rs. 2160
C.P = Rs. 2400
profit percent = 15%
S.P = ?
S.P=(100+ Profit %)100×C.P=100+15100×2400=115100×2400
S.P. = Rs. 2760.
When the profit percent is 15%, the S.P. is Rs. 2760.
Total C.P. of two fans is 2400 + 2400 = Rs. 4800.
Total S.P. of two fans is 2160 + 2760 = Rs. 4920.
Total SP > Total C.P
∴ Total profit = Total S.P – Total C.P = 4920-4800 Profit = Rs. 120.

Question 5.
A storekeeper sells a book at a 15% gain. Had he sold it for Rs. 18 more. He would have gained 18%. Find the cost price of the book.
Answer:
Let the C.P be Rs. x
gain % = 15%
KSEEB Solutions for Class 8 Maths Chapter 9 Commercial Arithmetic Ex. 9.2 3
Had he sold it for Rs. 18 more the new S.P.
would be Rs. 115×100 . This is equal to S.P
When the gain percent is 18%
S.P when gain percent is 18% is
KSEEB Solutions for Class 8 Maths Chapter 9 Commercial Arithmetic Ex. 9.2 4
118 x – 115 x = 1800
3 x = 1800
x = 18003
x = 600
∴ Cost price = Rs.600.

Question 6.
The cost price of 12 pens is equal to the selling price of 10 pens. Find the profit percentage.
Answer:
Let the C.P of one pen be Rs. 1
∴ C.P of 12 pens = Rs. 12
Given S.P. of 10 pens = C.P. of 12 pens.
S.P. of 10 pens = Rs. 12 C.P of 10 pens = Rs. 10
∴ S.P > C.P So there is gain
Gain = S.P – C.P= 12 – 10 = 2
Gain percent = GainC.P × 100
= 210 × 100 = 20 %
Gain percent = 20%

All Chapter KSEEB Solutions For Class 8 maths

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All Subject KSEEB Solutions For Class 8

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