In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 5 Squares, Square Roots, Cubes, Cube Roots Ex 5.6 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 5 Squares, Square Roots, Cubes, Cube Roots Ex 5.6 pdf, free KSEEB SSLC Class 8 Maths Chapter 5 Squares, Square Roots, Cubes, Cube Roots Ex 5.6 pdf download. Now you will get step by step solution to each question.

**Karnataka State Syllabus Class 8 Maths Chapter 5 Squares, Square Roots, Cubes, Cube Roots Ex 5.6**

## Karnataka Board Class 8 Maths Chapter 5 Squares, Square Roots, Cubes, Cube Roots Ex 5.6

Question 1.

Looking at the pattern fill in the gaps in the followings.

Answer:

2 | 3 | 4 | -5 | 6 | 8 | -9 |

2^{3}= 8 | 3^{3} = 27 | 4^{3} = 64 | -5^{3} = -125 | 6^{3} = 216 | 8^{3} = 512 | -9^{3} = -729 |

Question 2.

Find the cubes of the first five odd natural numbers and the cubes of the first five even natural numbers. What can you say about, the parity of the odd cubes and even cubes?

Answer:

1^{3} = 1 × 1 × 1 = 1

2^{3} = 2 × 2 × 2 = 8

3^{3} = 3 × 3 × 3 = 27

4^{3} = 4 × 4 × 4 = 64

5^{3} = 5 × 5 × 5=125

6^{3} = 6 × 6 × 6 = 216

7^{3} = 7 × 7 × 7 = 343

8^{3 }= 8 × 8 × 8 = 512

9^{3} = 9 × 9 × 9 = 729

10^{3} = 10 × 10 × 10 = 1000

The cube of an odd number is odd and the cube of an even number is even.

Question 3.

How many perfect cubes you can find from I to 100? How many from -100 to 100?

Answer:

From 1 to 100 there are 4 perfect cubes. 1, 8, 27, 64 From -100 to 100 there are 9 perfect cubes -64, -27, -8, -1, 0, 1, 8, 27, 64

Question 4.

How many perfect cubes are there from 1 to 500? How many are the perfect square among these cubes?

Answer:

From 1 to 500 there are 7 perfect cubes and 2 of these are perfect squares.

Perfect cubes 1, 8, 27, 64, 125, 216, 343,

Perfect squares are 1 = 1^{2} = 1^{3} and 64 = 8^{2} = 4^{3}

Question 5.

Find the cubes of 10, 30, 100, 1000. What can you say about the zeros at the end?

Answer:

10^{3}= 10 x 10 x 10 = 1.000 (3 zeros)

30^{3} = 30 × 30 × 30 = 27000 (3 zeros)

100^{3} = 100 × 100 × 100 = 1000000 (6 zeros)

1000^{3} = 1000 × 1000 × 1000 = 1000000000 (9 zeros)

The number of zeros at the end are always multiple of 3.

Question 6.

What are the digits in the units place of the cubes of 1,2,3,4,5,6,7,8,9,10? Is impossible to say that a number is not a perfect cube by looking at the digit in the units place of the given number, just like you did for squares?

Answer:

1^{3}=1

2^{3} = 8

3^{3} = 27

4^{3 }= 64

5^{3} = 125

6^{3} = 216

7^{3} = 343

8^{3} = 512

9^{3} = 729

10^{3} = 1000

∴ It is not possible to say whether the number is a perfect cube (or) not looking at the digit in unit place.

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