# KSEEB Solutions for Class 8 Maths Chapter 3 Axioms, Postulates, and Theorems Additional Questions

In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Additional Questions for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Additional Questions pdf, free KSEEB SSLC Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Additional Questions pdf download. Now you will get step by step solution to each question.

## Karnataka State Syllabus Class 8 Maths Chapter 3 Axioms, Postulates and Theorems Additional Questions

Question 1.
Choose the correct option
(i) If a = 6 and b = a, then b = 60 by _______
A. Axiom 1
B. Axiom 2
C. Axiom 3
D. Axiom 4
Solution:
A. Axiom 1

(ii) Given a point on the plane, one can draw ________
A. unique
B. two
C. finite numberd
D. infinitely many
Solution:
(D) Infinetly many lines through that point.

(iii) Given two points in a plane, the number of lines which can be drawn to pass through these two points is ________
A. Zero
B. exactly one
C. at most one
D. more than one
Solution:
(B) Exactly one

(iv) If two angles are supplementary, then their sum is
A. 90°
B. 180°
C. 270°
D. 360°
Solution:
(B) 180°

(v) The measure of an angle which is 5 times its supplement is _________
A. 30°
B. 60°
C. 120°
D. 150°
Solution:
(D) 150°

Question 2.
What is the difference between a pair of supplementary angles and a pair of complementary angles?
Solution:
If the sum of two angles is 180° then they are supplementary angles. If the sum of two angles is 90° then they are complementary angles.

Question 3.
What is the least number of non – collinear points required to determine a plane?
Solution:
Three (3)

Question 4.
When do you say two angles are adjacent?
Solution:
Two angles are said to be adjacent angles if they have a common vertex and a common side.

∠ AUV – ∠CVP = 70°
[corresponding angles]
∠QUB – ∠AUV = 70° [vertically opposite angles]
∠BUW + ∠DWU = 180° [Interior angles on the same side of transversal]
∠BUW + 110°= 180°
∠BUW = 180-110° = 70°
∠BUW = ∠AUS= 70° [vertically opposite angles]
∠AUS + ∠SUQ + ∠QUB = 180° ∠AUB is a straight angle]
70 + ∠SUQ + 70 = 180°
∠SUQ + 140° = 180°
∠SUQ = 180° – 140°
∠SUQ = 40°

Question 9.
What is the angle between the hours hand and minutes hand of a clock at (i) 1.40 hours (ii) 2.15 hours [use 1° = 60 minutes]
Solution:
i. 1.40 hours – 190°
ii. 2.15 hours – 22° 30′

Question 10.
How much would hour’s hand have moved from its position at 12 noon when the time is 4.24 p.m?
Solution:
144°

∠DOX = ∠BOX [ ∵OX−→− bisects ∠BOD]
∠DOX =∠COY [vertically opposite angles] ….(i)
∠BOX = ∠AOY
[vertically opposite anglesj … (ii)
From (i) and (ii)
[vertically opposite] …(ii)
∠AQY – ∠COY [Axiom 1]
∴ OX−→− bisects ∠AOC

∴ ∠DCY = 180° – ∠CDE
∠BCX + ∠BCD + ∠DCY = 180° [∵ XCY is straight angle]
180 – ∠ABC + ∠BCD + 180 – ∠CDE = 180° [By substituting]
360 – ∠ABC + ∠BCD – ∠CDE – 180°
360 – 180 – ∠ABC – ∠BCD + CDE
180° = ∠ABC – ∠BCD + ∠CDE
or
∠ABC – ∠BCD + ∠CDE = 180°

Question 17.
Consider two parallel lines and a transversal among the measures of 8 angles formed how many distinct numbers are there?
Solution:
There will be two distinct numbers.

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