KSEEB Solutions for Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3

In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3 pdf, free KSEEB SSLC Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3 pdf download. Now you will get step by step solution to each question.

Karnataka State Syllabus Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3

Karnataka Board Class 8 Maths Chapter 2 Algebraic Expressions Ex 2.3

Question 1.
Complete the following table of products of two monomials

Question 2.
Find the products
i. (5x + 8) 3x
ii. (-3 pq)(-15 p³q² – q³)
iii. 2×5(3a3−3b3)
iv. -x²(x – 15)
Answer:
i. 5x . 3x + 8.3x = 15x² + 24x

ii. (- 3pq) (- 15p³q² – q³)
= (- 3pq) (- 15p³q²) – (- 3pq)(q³)
= 45 p⁴q³ + 3 pq⁴

iii. 2×5×3a3−2×5×3b3=6xa35−6xb33

iv. (-x²)x – (-x²) 15
= -x³ + 15x²

Question 3.
Simplify the following :
i. (2xy -xy) (3xy – 5)
ii. (3xy² +1) (4xy – 6xy²)
iii. (3x² + 2x) (2x² + 3)
iv. (2m³ + 3m) (5m – 1)
Answer:
i. 2x y (3xy – 5) – 2xy(3xy – 5) = 6x²y² – 10xy – 6x²y² + 10xy

ii. 3xy² (4xy – 6xy²) +1 (4xy – 6xy²) = 12 x²y3 – 18x²y4 + 4xy – 6xy²

iii. 3x²(2x² + 3) + 2x(2x² + 3] = 6x⁴ + 9x² + 4x³ + 6x

iv. 2m³ (5m – 1) + 3m(5m – 1) = 10m⁴ – 2m³ + 15m² – 3m

All Chapter KSEEB Solutions For Class 8 maths

—————————————————————————–

All Subject KSEEB Solutions For Class 9

*************************************************

I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good marks in your exam.

If these solutions have helped you, you can also share kseebsolutionsfor.com to your friends.

Best of Luck!!