In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 16 Mensuration Ex 16.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 16 Mensuration Ex 16.2 pdf, free KSEEB SSLC Class 8 Maths Chapter 16 Mensuration Ex 16.2 pdf download. Now you will get step by step solution to each question.

**Karnataka State Syllabus Class 8 Maths Chapter 16 Mensuration Ex 16.2**

Question 1.

Find the total surface area and volume of a cube whose length is 12 cm.

Answer:

l = 12 cm

T.S.A of cube = 6 l² = 6 x 12² = 6 x 144 = 864 cm²

Volume of cube = P = (12)^{3} = 1728 cm^{3}

Question 2.

Find the volume of a cube whose surface area is 486 cm².

Answer:

T.S.A of a cube = 486 cm²

6^{12} = 486

l² = 4866

l² = 81

∴ l = √81 = 9 cm

Volume = l^{3} = 9^{3}= 729 cm^{3}

Question 3.

A tank, which is cuboidal in shape has a volume 6.4m^{3}. The length and breadth of the base are 2m and 1.6m respectively. Find the depth of the tank.

Answer:

V = 6.4 m^{3}

l = 2 m

b = 1.6 m

h = ?

Volume of cuboid = 6.4 m^{3}

l × b × h = 6.4

2 × 1.6 × h = 6.4

3.2h = 6.4

h = 6.43.2

h = 2m

h = 2m .

∴ The depth of the tank is 2 m.

Question 4.

How many m^{3} of soil has to be excavated from a rectangular well 28cm deep and whose base dimensions are 10cm and 8m. Also, find the cost of plastering its vertical walls at the rate of Rs. 15/m2.

Answer:

l = 10 m

b = 8

h = 28 m

Volume of soil = volume of cuboid

= l × b × h = 10 × 8 × 28 = 2240 m^{3}

2240 m^{3} of soil has to be excavated.

Area to be plastered = L.S.A of cuboid

= 2h(l + b)

= 2 × 28(10 + 8)

= 56 × 18

= 1008 m^{2}

The cost of plastering 1m² = Rs. 15

∴ The cost of plastering = 15 × 1008 = Rs. 15,120

Question 5.

A solid cubical box of fine wood costs Rs. 256 at the rate of Rs. 500/m3. Find its volume and length of each side.

Answer:

The cost of Rs. 500 is for 1m^{3}.

The cost of Rs. 256 is for

256500=128250=64125m3

∴ Volume of the wood = 64125m3 = 0.512 m^{3}

Volume = 0.512m

l^{3} = 0.512

l=0.512−−−−√3

l = 0.8 m²

= 0.8 × 100

Length of the side = 80cm, l= 80cm

**All Chapter KSEEB Solutions For Class 8 maths**

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