In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 11 Congruence of Triangles Ex 11.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 11 Congruence of Triangles Ex 11.2 pdf, free KSEEB SSLC Class 8 Maths Chapter 11 Congruence of Triangles Ex 11.2 pdf download. Now you will get step by step solution to each question.
Karnataka State Syllabus Class 8 Maths Chapter 11 Congruence of Triangles Ex 11.2
In the adjoining figure PQRS is a rectangle. Identify the congruent triangles formed by the diagonals.
Δ PSR ≅ Δ PQR, Δ POQ ≅ Δ SOR
Δ SPQ ≅ Δ SRQ, Δ POS ≅ Δ QOR
In the figure ABCD is a square. M, N, O & P are the midpoints of sides AB, BC, CD and DA respectively. Identify the congurent triangles.
Δ APM ≅ Δ BMD ≅ Δ CNO ≅ Δ DOP
In a triangle ABC, AB = AC. Points G on AB and D on AC are such that AE = AD. Prove that triangles BCD and CBE are congruent.
In the figure AB = AC (data)
∴∠ABC = ∠ACB
[Base angles of an isosceles triangle]
AB = AC(data)
AE = AD(data)
AB – AE = AC – AD (Axiom 3)
BE = DC
In Δ BCD and Δ CBE
∠BCD = ∠EBC
BE = DC (Proved)
BC = BC (Common side)
∴ Δ BCD= Δ CBE [SAS postulate]
In the adjoining figure the sides BA and CA have been produced such that BA = AD and CA = AE prove that DE || BC (hint : use the concept of alternate angles.)
Δ AED and Δ ABC
AE = AC (data)
AD = AB (data)
∠EAD = ∠BAC
[Vertically opposite angles]
∴ Δ AED = ABC
∴ ∠AED = ∠ACB [Congruent triangle property]
But these are alternate angles.
∴ DE || BC
Consequences of SAS postulate.
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