KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.7

In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.7 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.7 pdf, free KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.7 pdf download. Now you will get step by step solution to each question.

Karnataka State Syllabus Class 8 Maths Chapter 10 Exponents Ex 10.7

Question 1.
Use the laws of exponents and simplify
Answer:

Question 2.
What is the value of (103)2×10−4102
Answer:

Question 3
Simplify:
[b−3⋅b7⋅(b−1)2(−b)2(b2)3]−2
Answer:

Question 4.
Find the value of each of the following expressions.

(a). (3²)² – (-2)³)² – (-(5)²)²
= 3⁴ – (- 2 x – 2 x – 2)² – (-5² )²
= 3⁴ – (-2³)² – 5⁴
= 81 – 2⁶ – 625
= 81- 64 – 625
= 81 – 689
= – 608

(b). ((0.6)²)⁰ – ((4.5)⁰)^-2
= (0.6)^{2 x 0} – (4.5)^{0 x -2}
= (0.6)⁰ – (4.5)⁰
= 1 – 1
= 0

(c).

All Chapter KSEEB Solutions For Class 8 maths

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All Subject KSEEB Solutions For Class 8

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