# KSEEB Solutions for Class 8 Maths Chapter 10 Exponents Ex 10.6

In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.6 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.6 pdf, free KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.6 pdf download. Now you will get step by step solution to each question.

### Karnataka State Syllabus Class 8 Maths Chapter 10 Exponents Ex 10.6

Question 1.
Simplify
(i). (23)8×(64)3
(ii). (1.8)6 × (4.2)-3
(iii). (0.0006)3(0.015)−4    Question 2.
Can it happen that for some integer m ≠ 0 (425)m = (25)m2 ? ∴ m2 = 2m
m.m=2m
m=2
It can happen if m=2

Question 3.
Find all positive integers m, n such that (3m)n = 3m × 3n
(3m)n = 3m × 3n
3mn = 3m+n
mn = m + n
2 × 2 = 2 + 2
∴ m = 2, n = 2
(m, n) = (2, 2)

All Chapter KSEEB Solutions For Class 8 maths

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All Subject KSEEB Solutions For Class 8

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