In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.4 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.4 pdf, free KSEEB SSLC Class 8 Maths Chapter 10 Exponents Ex 10.4 pdf download. Now you will get step by step solution to each question.

**Karnataka State Syllabus Class 8 Maths Chapter 10 Exponents Ex 10.4**

Question 1.

Simplify

(i) (25)6×(33)2(26)5×(32)3

(ii) (5−3)2×34(3−2)−3×(53)−2

Answer:

Question 2.

Can you find two integers m and n such that 2m+“ = 2m”?

Answer:

m + n = mn

2 + 2 = 2 x 2

4 = 4

∴ m = 2 & n = 2

Question 3.

If (2^{m})^{4} = 4^{6} find the value of m.

Answer:

(2^{m})^{4} = 4^{6} (a^{m})^{n} = a^{mn}

(2^{m})^{4} = 4^{6}

(2^{m})^{4} = (2^{2})^{6}

2^{m × 4} = 2^{2 × 6}

2^{4m} = 2^{12}

∴ 4m = 12

m =

m = 3

**All Chapter KSEEB Solutions For Class 8 maths**

—————————————————————————–**All Subject KSEEB Solutions For Class 8**

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