# KSEEB Solutions for Class 8 Maths Chapter 1 Playing with Numbers Ex 1.2

In this chapter, we provide KSEEB SSLC Class 8 Maths Chapter 1 Playing with Numbers Ex 1.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 8 Maths Chapter 1 Playing with Numbers Ex 1.2 pdf, free KSEEB SSLC Class 8 Maths Chapter 1 Playing with Numbers Ex 1.2 pdf download. Now you will get step by step solution to each question.

## Karnataka Board Class 8 Maths Chapter 1 Playing with Numbers Ex 1.2

Question 1.
In the following find the digits represented by the letters. Here : 3 + 4 = 7 ∴ B = 4 Here 6 + A = 1 ∴ A = 5
6 + 5 = 11 is written in units place and 1 is carried.
∴ 1 + 1 + 2 = B
∴ B = 4 Here A × A is A.
Hence A = 0, 1, 5, or 6 If A = 1 we get 21 × 1 = 21 but the product is 12A.
If A = 5 then 25 × 5 = 125.
∴ A = 5 Here A + A = A
Hence A = 0  Answer: Here A × A = A
Hence A = 0, 1, 5 or 6
If A = 1, then 11 × 11 = 121
∴ A = 1 and B = 2 3A × A
36 × 6
216
∴ A = 6 & B = 1

Question 2.
In the adjacent sum A, B, C are consecutive digits. In the third row A, B, C appear in some order. Find A, B, C. ∴ A = 3, B = 4 and C = 5

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