# Line slope calculator 8x+7y=78

**Straight line given by points A[1; 10] and B[8; 2]**

## Calculation:

**Slope-intercept form of line:**y = -1.1429x+11.1429

**Canonical form of the line equation:**8x+7y-78 = 0

**Parametric form of the line equation:**

x = 7t+1

y = -8t+10 ; t ∈ R

**Slope:**m = -1.1429

**Slope angle of line: φ =**-48°48'51″ = -0.852 rad

**X intercept:**x

_{0}= 9.75

**Y intercept:**y

_{0}= q = 11.1429

**Distance line from the origin:**d

_{0}= 7.3376

**The length of the segment AB: |AB| =**10.6301

**Vector: AB =**(7; -8)

**Normal vector: n =**(8; 7)

**Midpoint of the segment AB: M =**[4.5; 6]

**Perpendicular Bisector equation:**7x-8y+16.5 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (8; 2) ; |OB| = 8.2462**

**Scalar product OA .OB = 28**

**Angle ∠ AOB = 70°15'11″ = 1.2261 rad**