KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1

In this chapter, we provide KSEEB SSLC Class 10 Maths Solutions Solutions Chapter 9 Polynomials Ex 9.1 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 10 Maths Solutions Solutions Chapter 9 Polynomials Ex 9.1 pdf, free KSEEB SSLC Class 10 Maths Solutions Solutions Chapter 9 Polynomials Ex 9.1 pdf download. Now you will get step by step solution to each question.

Karnataka State Syllabus Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1

Question 1.
The graph of y = p(x) are given in the following figure, for some polynomials p(x). Find the number of zeros of p(x) in each case.
KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 1
Solution:
(i) Graph of y = p(x) will not intersects x-axis.
∴ No zero for this polynomial.
KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 2

(ii) Graph of y = p(x) intersects x-axis at only one point.
∴ Only one zero is there for this polynomial.
KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 3

(iii) y = p(x) intersects x-axis at 3 points.
∴ It has 3 zeroes.
KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 4

(iv) y = p(x) intersects x-axis at 2 points.
∴ Two zeroes for this polynomial.
KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 5

(v) y = p(x) intersects x-axis at four (4) points.
∴ Four zeroes for this polynomial.
KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 6

(vi) y = p(x) intersects x-axis at three (3) points.
∴ This polynomial has 3 zeroes.
KSEEB SSLC Class 10 Maths Solutions Chapter 9 Polynomials Ex 9.1 7

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