KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2

In this chapter, we provide KSEEB SSLC Class 10 Maths Solutions Solutions Chapter 13 Statistics Ex 13.2 for English medium students, Which will very helpful for every student in their exams. Students can download the latest KSEEB SSLC Class 10 Maths Solutions Solutions Chapter 13 Statistics Ex 13.2 pdf, free KSEEB SSLC Class 10 Maths Solutions Solutions Chapter 13 Statistics Ex 13.2 pdf download. Now you will get step by step solution to each question.

Karnataka State Syllabus Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2

Question 1.
The following table shows the ages of the patients admitted in a hospital during a year :
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 1
Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency ?
Solution:
(i) Here the maximum class interval is 35 – 45. This class interval has mode
l = 35, f1 = 23, f0 = 21, f2 = 14, h = 10
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 1.1
∴ Mode = 36.8 years

(ii) Mean (X¯¯¯¯) : Step Deviation Method:
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 1.2
Here, a = 30
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 1.3
= 30 + 5.37
= 35.37
∴ Mode = 36.8
∴ Mean = 35.37
Hence Age group 36.8 patients are admitted more in number.
Mean age group patients are 35.57

Question 2.
The following data gives the information on the observed lifetimes (in hours) of 225 electrical components:
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 2
Determine the modal lifetimes of the components:
Solution:
Class interval which has mode = 60 – 80
Here, l = 60, f1 = 61, f0 = 52, f2 = 38, h = 20
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 2.1
∴ Mode = 65.63 Hours

Question 3.
The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also. And the mean monthly expenditure :
Solution:
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 3
Solution:
(i) Mode is in class interval 1500 – 2000
Here, l = 1500, f1 = 40, f0 = 24, f2 = 33, h = 500
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 3.1

(ii) Mean (X¯¯¯¯): Step Deviation Method:
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 3.2
Here, a = 2750
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 3.3
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 3.4
= 2750 – 87.50
= 2662.5
∴ Modal monthly expenditure = 1847.8
∴ Mean Monthly expenditure = Rs. 2662.5

Question 4.
The following distribution gives the state- wise teacher-student ratio in higher secondary schools of India. Find the mode and mean of this data. Interpret the two measures.
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 4
Solution:
(i) Class interval which has mode 30 – 35
Here, l = 30, f1 = 10, f0 = 9, f2 = 3, h = 5
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 4.1
∴ Mode = 30.6
(ii) Mean (X¯¯¯¯) : Step Deviation Method :
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 7
By Step Deviation Method:
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 4.3
= 32.5 – 3.3
= 29.2
∴ Mode = 30.6
∴ Mean = 29.2
We conclude that more number of states has teacher-student ratio about 30.6.
Mean of Age ratio is 29.2.

Question 5.
The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 5
Find the mode of the data.
Solution:
Class interval which has mode is = 4000 – 5000
Maximum frequency is
Here, l = 4000, f1 = 18, f0 = 4, f2 = 9, h = 1000
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 5.1
= 4000 + 608.7
= 4608.7
∴ Mode = 4608.7 runs.

Question 6.
A student noted the number of cars passing through a spot on a road for 100 periods each of 3 minutes and summarised it in the table given below. Find the mode of the data :
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 6
Solution:
Class interval which has mode is 40- 50
Maximum frequency is 20.
Here, l = 40, f1 = 20, f0 = 12, f2 = 11, h = 10
KSEEB SSLC Class 10 Maths Solutions Chapter 13 Statistics Ex 13.2 Q 6.1
= 40 + 4.7
= 44.7
∴ Mode = 44.7 cars.

All Chapter KSEEB Solutions For Class 10 Maths

—————————————————————————–

All Subject KSEEB Solutions For Class 10

*************************************************

I think you got complete solutions for this chapter. If You have any queries regarding this chapter, please comment on the below section our subject teacher will answer you. We tried our best to give complete solutions so you got good marks in your exam.

If these solutions have helped you, you can also share kseebsolutionsfor.com to your friends.

Best of Luck!!

Leave a Comment

Your email address will not be published.